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Convert black to transparent without losing red gradient
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clinton

Joined: 01 Jul 2010
Posts: 2



PostPosted: Thu Jul 01, 2010 10:51 am    Post subject: Convert black to transparent without losing red gradient Reply with quote

I've attempted this for 3 days now, having followed several guides and links from google and have had no luck. Please forgive me for making this my first post and seeking some help here.

I'd like to remove the black from the attached image without losing any of the red gradient. Preferably I'd like to make it transparent as it will sit on a (mostly) black background that will still complete the effect. With the transparency I will be free to alter the background of the image without worrying about a "black box" around the flame area.

Any help and or advice would be greatly appreciated.
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hawkeye

Joined: 14 May 2009
Posts: 2377
Location: Mesa, Az

OS: Windows 7 Pro 64 bit

PostPosted: Thu Jul 01, 2010 11:15 am    Post subject: Reply with quote

I didn't spend the time it would take to get it right but it should give you the idea...cut out the yellow with the pen tool copy it to a new layer, then added a gradient to a layer below.
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clinton

Joined: 01 Jul 2010
Posts: 2



PostPosted: Thu Jul 01, 2010 12:55 pm    Post subject: Reply with quote

Your suggestion put me on the right track. Here's what I did:

- Used the pen tool to pull the flame into it's own layer
- Threw out everything else
- Played with the Gradient tool and created a gradient that would be heavy in the middle but drop quickly near the edges.
- Created the gradient
- Created a new layer with just black for comparison to the original
- I'm happy!

I've attached screenshots for you to see the results. Thank you for your time.

Considering I just started using CS4 on Monday, I think I'm kicking some butt on the learning curve here :)
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Patrick
Administrator
Administrator

Joined: 14 Feb 2003
Posts: 11945
Location: Harbinger, NC, U.S.A.


PostPosted: Thu Jul 01, 2010 1:01 pm    Post subject: Reply with quote

Excellent. Nice jon, hawkeye and thanks for sharing that, clinton. :) Welcome.

Patrick

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